Question

How much 0.2M HCl can be made from 5.0mL of a 12.0M
HClSolution?

Answer 1

Answer: The volume of 0.10 M NaOH required to neutralize 30 ml of 0.10 M HCl is, 30 ml.

Explanation:

According to the dilution law,

`M_1V_1=M_2V_2`

where,

`M_1` = molarity of stock
`HCl` solution = 12.0 M

`V_1` = volume of stock
`HCl`solution = 5.0 ml

`M_2` = molarity of dilute
`HCl` solution = 0.2 M

`V_2` = volume of dilute
`HCl` solution = ?

Putting in the values we get:

`(12.0M)* 5.0=0.2* V_2`

`V_2=300ml`

Therefore, 300 ml of 0.2M HCl can be made from 5.0mL of a 12.0M
`Hcl` solution.