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1 vote
Find the coefficient of x^25 in (1 +x +x^8)^10

asked
User Drop
by
6.8k points

1 Answer

7 votes

The only way to get a term containing
x^(25) is to take 6 copies of 1, 1 copy of
x, and 3 copies of
x^8 (since 6+1+3=10, and 6*0+1*1+3*8=25). So this term has a coefficient of


(10!)/(6!1!3!)=840

answered
User BinaryEvolved
by
7.7k points

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