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An urn contains three red balls, five white balls, and two black balls. Four balls are drawn from the urn at random without replacement. For each red ball drawn, you win $6, and for each black ball drawn, you lose $9. Let X represent your net winnings Compute E(X), your expected net winnings E(x)

1 Answer

3 votes

Answer:

0

Explanation:

total number of balls = 3+5+2= 10

Probability of getting red P(R) = 3/10

Probability of getting white P(W) = 5/10

Probability of getting black P(B) = 2/10

for each red ball drawn you win $6 and for each black ball drawn you loose $9 dollars

E(X)= 6×3/10 +0×5/10 -9×2/10= 0

E(X)= 0

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