What is the boiling point of an benzene solution that freezes at 0.3 degrees C? Normal freezing point is 5.5 and the normal boiling point is 80.1 degrees C. Kfp = 5.12 K/m and K…

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asked Jan 8, 2020 78.3k views

1 Answer

Johnny Westlake · Answer 1 · 2020-01-13T08:23:58+0000

Answer: The boiling point of an benzene solution is

Step-by-step explanation:

Depression in freezing point is given by:

$\Delta T_f=i* K_f* m$

$\Delta T_f=T_f^0-T_f=(5.5-0.3)^0C=5.2^0C=5.2K$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

K_f = freezing point constant =
5.12K/m

m= molality

5.2=1* 5.12* m

m=1.015

Elevation in boiling point is given by:

$\Delta T_b=i* K_b* m$

$\Delta T_b=Tb-Tb^0=(Tb-80.1)^0C$ = elevation in boiling point

i= vant hoff factor = 1 (for non electrolyte)

K_b = boiling point constant =
2.43K/m

m= molality = 1.015

(T_b-80.1)^0C=1* 2.43* 1.015

T_b=82.57^0C

Thus the boiling point of an benzene solution is