Question

If gas in a sealed container has a pressure of 50 kPa at 300 K, what will the pressure be if the temperature rises to 360 K?

60 kPa

161 kPa

41 kPa

16 kPa

Answer 1

`\boxed{\text{60 kPa}}`

Step-by-step explanation:

The volume and number of moles are constant, so we can use Gay-Lussac’s Law:

At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

`(p_(1))/(T_(1)) = (p_(2))/(T_(2))`

Data:

p₁ = 50 kPa; T₁ = 300 K

p₂ = ?; T₂ = 360 K

Calculation:

`\begin{array}{rcl}(50)/(300) & = & (p_(2))/(360)\\\\(1)/(6) & = & (p_(2))/(360)\\\\(360)/(6) & = & p_(2)\\\\p_(2) & = & \mathbf{60}\\\end{array}`

`\text{The new pressure will be $\boxed{\textbf{60 kPa}}$}`