Question

Please Help! I don't know where to start with this, please show all work!

What is the vertex form of the equation?

y = -x^2 + 12x - 4

Answer 1

Hey!

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Formula's:

x_v = -b/2a

y_v = ax² + bx + c

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Parabola Params:

a = -1

b = 12

c = 4

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Solve for
`x_(v)`

`x_(v) = (-b)/(2a)`

`x_(v) = (-12)/(2(-1))`

`x_(v) = -6`

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Solve for
`y_(v)`

Use -6 for
`x_(v)`

`y_(v) = -6^2 + 12(6) - 4\\`

`y_(v) = -36 + 72 - 4`

`y_(v) = 32`

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Answer:

(6, 32)

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Hope This Helped! Good Luck!