asked 35.7k views
9 votes
herlene has 5.05 in quarters and dimes. The number of quarters is one more than twice the number of dimes. Find the number she has of each kind.

asked
User Laron
by
8.8k points

1 Answer

8 votes

Answer:

Herlene has 8 dimes and 17 quarters

Explanation:

System of Equations

Let's call:

x = number of dimes Herlene has

y = number of quarters Herlene has

Since each dime has a value of $0.10 and each quarter has a value of $0.25, the total money Herlene has is 0.10x+0.25y.

We know this amount is $5.05, thus:

0.10x + 0.25y = 5.05 [1]

It's also given the number of quarters is one more than twice the number of dimes, i.e.:

y = 2x + 1 [2]

Substituting in [1]:

0.10x + 0.25(2x + 1) = 5.05

Operating:

0.10x + 0.5x + 0.25 = 5.05

0.6x = 5.05 - 0.25

0.6x = 4.8

x = 8

From [2]:

y = 2*8 + 1 = 17

y = 17

Herlene has 8 dimes and 17 quarters

answered
User Michael Mulich
by
9.0k points

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