Question

(8z - 12) + (6z +90)

Answer 1

(8z - 12) + (6z +90)

pretend that there is a 1 in front of the second bracket

(8z - 12) +1 (6z +90)

mutiply the second bracket by 1

(1)(6z)= 6z

(1)(90)= 90

8z-12+6z+90

8z+6z-12+90

Answer: 14z+78

Answer 2

Explanation:

(8z - 12) + (6z +90)

add common things

14z+78

this is as simplest at it will go