Answer:
P = 0.001625 
yes, it did
Explanation:
given data 
affective ones = 2%
spark plugs = 8000
defective = 13 
to find out 
experimental probability that the next sparkplug will be defective and Did the mannufacturer reach its goal
solution 
we know that there are 13 are defective out of 8000 
so P = 13 ÷ 8000 
P = 0.001625 
 so that P( the next sparkplug will be defective) is = 0.001625
and 
yes, we mannufacturer to reach goal
because 0.001625 < .02 
So, the goal is reached as the experimental probability is less than 2%