asked 80.3k views
1 vote
A 0.210 mL sample of very-low-density lipoprotein (VLDL) has a mass of 206 mg. What is the density of the VLDL?

asked
User Aneurinc
by
8.0k points

2 Answers

3 votes

Final answer:

The density of the VLDL sample is 0.981 g/mL.

Step-by-step explanation:

The density of a substance is calculated by dividing the mass of the substance by its volume. In this case, the mass of the VLDL sample is 206 mg and the volume is 0.210 mL. To convert the mass to grams, divide it by 1000:

206 mg ÷ 1000 = 0.206 g

Now, divide the mass by the volume:

0.206 g ÷ 0.210 mL = 0.981 g/mL

Therefore, the density of the VLDL sample is 0.981 g/mL.

answered
User ValentinH
by
7.8k points
0 votes

Answer:

0.980 g/mL

Step-by-step explanation:

We know that the density of an object can be measured by dividing its mass (g) to its volume (mL).

Formula

D=m/v

Given data:

Mass= 206 mg

Volume= 0.210 mL

First of all we will convert the mg into gram.

206 mg= 0.206 g

because one gram contain thousand miligrams.

Now we will put the values in formula:

D= 0.206 g/ 0.210 mL= 0.98 g/mL

So the density of VLDL is 0.98 g/mL.

answered
User Tasawer Khan
by
7.9k points
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