Question

The equation of the line that passes through and how did you solve it?

Answer 1

`\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-4}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{-1}-\underset{x_1}{(-2)}}}\implies \cfrac{-4+7}{-1+2}\implies \cfrac{3}{1}\implies 3`

`\bf \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{3}[x-\stackrel{x_1}{(-2)}]\implies y+7=3(x+2) \\\\\\ y+7=3x+6\implies y=3x-1`

Answer 2

3

Explanation:

to find the slope you do the formula

y2-y1 divided by x2-x1. (keep it in fraction form). it doesnt really matter what order you put the points as but keep it consistent