Light propagating in air strikes the surface of a lake. The reflected ray makes 62° angle with the normal. What angle does the refracted ray in the water makes with the normal. …

Question

asked Oct 1, 2020 33.3k views

1 Answer

Guildencrantz · Answer 1 · 2020-10-06T09:32:43+0000

Answer:

(a) 42°

Step-by-step explanation:

According to the law of reflection:

Angle of incidence = Angle of reflection

So, angle of reflection = 62°

Angle of incidence = 62°

For refraction,

Using Snell's law as:

$n_i* {sin\theta_i}={n_r}*{sin\theta_r}$

Where,

${\theta_i}$ is the angle of incidence ( 62.0° )

${\theta_r}$ is the angle of refraction ( ? )

${n_r}$ is the refractive index of the refraction medium (water, n=1.33)

${n_i}$ is the refractive index of the incidence medium (air, n=1)

Hence,

$1* {sin62.0^0}={1.33}*{sin\theta_r}$

Angle of refraction =
sin^(-1)0.6639 = 42°