Question

Problem 2: (15 pts) A 10-m high cylindrical container is half-filled at the bottom with water of density =1000 kg/m3 while the top half is filled with oil of specific gravity of 0.85. What is the pressure difference between the top and bottom of the container?

Answer 1

I don't get it I don't get it

Step-by-step explanation:

Answer 2

`\Delta p = 90.7 kPa`

Step-by-step explanation:

specific gravity of oil is
`= (\rho_(oil))/(\rho_w)`

`\rho_(oil) = 0.85*1000 = 850 kg/m3`

we know that

change in pressure for oil is given as

`\Delta p = \rho gh`

here density and h is for oil

`\Delta p = 850*5 *9.81 = 41,692.5 kPa`

change in pressure for WATER is given as

`\Delta p = \rho gh`

here density is for water and h is for water

`\Delta p = 1000*5 *9.81 = 49,050 kPa`

pressure change due to both is given as

`\Delta p = 41692.3 + 49050 = 90742.5 N/m2`

`\Delta p = 90.7 kPa`