Question

Gaseous chlorine is held in two separate containers at identical temperature and pressure. The volume of container 1 is 1.30 L, and it contains 6.70 mol of the gas. The volume of container 2 is 2.33 L. How many moles of the gas are in container 2?

Answer 1

According to the Avogadro's Law, the volume of the gas is directly proportional to the number of moles of the gas at constant pressure and temperature. This means the correct answer is 12.0 mol

Answer 2

Answer : The number of moles of gas are in container 2 are 12.008 moles.

Explanation :

According to the Avogadro's Law, the volume of the gas is directly proportional to the number of moles of the gas at constant pressure and temperature.

`V\propto n`

or,

`(V_1)/(V_2)=(n_1)/(n_2)`

where,

`V_1` = initial volume of gas in container 1 = 1.30 L

`V_2` = final volume of gas in container 1 = 2.33 L

`n_1` = initial moles of gas in container 2 = 6.70 mole

`n_2` = final moles of gas in container 2 = ?

Now put all the given values in the above formula, we get the final moles of the gas.

`(1.30L)/(2.33L)=(6.70mole)/(n_2)`

`n_2=12.008mole`

Therefore, the number of moles of gas are in container 2 are 12.008 moles.