Question

A kangaroo jumps straight up with an initial vertical velocity of 2.4\,\dfrac{\text{m}}{\text{s}}2.4 sm​ 2, point, 4, space, start fraction, m, divided by, s, end fraction. We want to find the maximum height of the jump.

Answer 1

it can jump upto maximum height of 0.29 m

Step-by-step explanation:

Initial velocity of the Kangaroo when it jumps upwards is given as

`v_i = 2.4 m/s`

final velocity of the kangaroo is given as

`v_f = 0`

now we know that acceleration is due to gravity

`a = -g`

now in order to find maximum height we know that we can use kinematics equation

`v_f^2 - v_i^2 = 2a d`

`0 - 2.4^2 = 2(-9.81) d`

`d = 0.29 m`

so it can jump upto maximum height of 0.29 m