Question

PHYSICS!! 30 PTS...

The mass of a pencil sitting on your desk about .25 meters from you is .006 kg. The mass of a typical teenager or young adult is 55 kg. What is the attractive force between them? (FG = G (m1 m2)/d2 where G = 6.67 x 10-11 N m2/kg2 )

Please show your work.
thank you!

Answer 1

Answer:
`3.52(10)^(-10) N`

Step-by-step explanation:

According to the law of universal gravitation, which is a classical physical law that describes the gravitational interaction between different bodies with mass:

`F=G(m_(1)m_(2))/(r^2)`

Where:

`F` is the module of the force exerted between both bodies

`G=6.674(10)^(-11)(m^(3))/(kgs^(2))` is the universal gravitation constant.

`m_(1)=0.006 kg` and
`m_(2)=55 kg` are the masses of the pencil and the teenager, respectively.

`r=0.25 m` is the distance between both bodies

Solving for
`F`:

`F=6.674(10)^(-11)(m^(3))/(kgs^(2))((0.006 kg)(55 kg))/((0.25 m)^2)`

`F=3.52(10)^(-10) N` This is the force of gravitational attraction between the pencil and the teenager, which is very small in this case