Question

Assuming an initial bracket of [1, 5] for bisection method, the first (at the end of 1 iteration) iterative value of the root of ((te)^-t)-.3=0 is?

Answer 1

After 1 iteration the value if the root will be α=3

Explanation:

Bisection takes the interval and selects the value in the middle of the interval as the root, then compares signes with the previous extremes of the interval.

`\alpha _1=((b-a))/(2)+a=(5-1)/(2)+1=3`