Question

Find each product
(8k+7) (6k+1)

Answer 1

Given,

first term a₁ = k

General term;

a_{n} = 2a_{n-1}

Hence, third term (n = 3);

a_{3} = 2 a_{3-1} = 2a_{2} = 2 * (2a_{2-1}) = 4a_{1} = 4k

Hence, the answer is B: 4k.