Answer: The standard deviation of test scores in the class is not less than 14.1
Explanation:
Let's suppose that the test scores follow a normal distribution. Besides, we have:
a) Standard deviation 

b) Significance level 

c) n=27
Using a) we can deduce that sample variance 
 .
. 
Since we want to prove if the population variance is less than 
 :
:
 (Null hypotesis) :
 (Null hypotesis) : 

 (Alternative hypotesis):
 (Alternative hypotesis): 

For test this kind of hypotesis (variance in one population) the correct test statistic is 
 , which under
, which under 
 have Chi-square distribution with n-1 degrees of freedom.
 have Chi-square distribution with n-1 degrees of freedom. 
Calculating the test statistic (
 is the value in
 is the value in 
 ) :
 ) : 

For this hypotesis (left one tailed test) the p-value is 
 where M follow a Chi-square distribution with n-1=26 degrees of freedom.You can check in a chi-square table that p-value=0.1986
 where M follow a Chi-square distribution with n-1=26 degrees of freedom.You can check in a chi-square table that p-value=0.1986
If 
 then there is no evidence to statistically reject
 then there is no evidence to statistically reject 
 . Therefore, the standard deviation of test scores in the class is not less than 14.1 (95% confidence level).
 . Therefore, the standard deviation of test scores in the class is not less than 14.1 (95% confidence level).