Question

Which two gases from the following will exhibit approximately the same rate of diffusion?

- Ethylene,
- C2H4 Ethane,
- C2H6 Carbon Monoxide,
- CO Carbon Dioxide,
- CO2

Answer 1

Answer: ethylene
`(C_2H_4)` and carbon monoxide
`(CO)`

Step-by-step explanation:

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

`\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}`

Thus gases having similar molar masses will have same rate of diffusion.

Molar mass of ethylene
`(C_2H_4)` = 28 g/mol

Molar mass of ethane
`(C_2H_6)` = 30 g/mol

Molar mass of carbon monoxide
`(CO)` = 28 g/mol

Molar mass of carbon dioxide
`(CO_2)` = 44 g/mol

As ethylene and carbon monoxide have same molar masses , they have same rate of diffusion.