Question

Find the magnitude of the electric field produced by a point charge q = 4.66 nanoCoulomb a distance r = 3.7 meters from the charge in units of N/C. Enter a number with two digits behind the decimal point.

Answer 1

Electric field, E = 3.0 N/C

Step-by-step explanation:

It is given that,

Charge particles,
`q=4.66\ nC=4.66* 10^(-9)\ C`

Distance from charge, r = 3.7 m

We need to find the magnitude of the electric field. The formula is given by :

`E=k(q)/(r^2)`

`E=9* 10^9* (4.66* 10^(-9))/((3.7)^2)`

E = 3.06 N/C

or

E = 3.0 N/C

So, the magnitude of the electric field produced by a point charge is 3.0 N/C. Hence, this is the required solution.