Question

Show me how to do this please for geometry!!

Answer 1

see explanation

Explanation:

Since the triangles are right use trigonometric ratios to find x and y

A

sin33° =
`(adjacent)/(hypotenuse)` =
`\frac{2.5}x}`

Multiply both sides by x

x × sin33° = 2.5 ( divide both sides by sin33° )

x =
`(2.5)/(sin33)` ≈ 4.590

tan33° =
`(opposite)/(adjacent)` =
`(2.5)/(y)`

Multiply both sides by y

y × tan33° = 2.5 ( divide both sides by tan33° )

y =
`(2.5)/(tan33)` ≈ 3.850

B

cos72° =
`(adjacent)/(hypotenuse)` =
`(6)/(x)`

Multiply both sides by x

x × cos72° = 6 ( divide both sides by cos72° )

x =
`(6)/(cos72)` ≈ 19.416

tan72° =
`(y)/(6)`

Multiply both sides by 6

6 × tan72° = y, thus

y ≈ 18.466