Question

If f(x)= 2^x, then f(log to the base 2 (5))=

Answer 1

Let's plug the value:

`f(x)=2^x \implies f(\log_2(5))=2^(\log_2(5))`

Recall that exponent and logarithm are inverse operations:

`a^(\log_a(b))=b`

So, we have

`2^(\log_2(5))=5`