Question

What is the area of 7 1/3 mm x 4 1/2 mm

Answer 1

`\displaystyle\bf\\7(1)/(3)~mm*4(1)/(2)~mm=\\\\\\=(7*3+1)/(3)*(4*2+1)/(2)=\\\\\\=(21+1)/(3)*(8+1)/(2)=\\\\\\=(22)/(3)*(9)/(2)=\\\\\\=(22*9)/(3*2)=\\\\\\=(11*3)/(1*1)=11*3=\boxed{\bf33~mm^2}`