Question

The molar enthalpy of fusion for water is 6.008 kJ/mol. What quantity of energy is released when 253 g of liquid water freezes?

Answer 1

Answer: 84400 Joules

Step-by-step explanation:

Molar enthalpy of fusion for water = 6.008 kJ/mol

Molar heat of fusion is the energy required to convert 1 mole of solid to 1 mole of liquid.

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

`\text{Number of moles of water}=(253g)/(18g/mol)=14.06moles`

1 mole of liquid water on freezing releases energy = 6.008 kJ

Thus 14.06 moles of liquid water on freezing releases energy =
`(6.008)/(1)* 14.06=84.4 kJ=84400Joules`

Thus 84400 Joules of energy is released when 253 g of liquid water freezes.