Question

The elevators in the John Hancock building in Chicago move 897 ft in 47 s. What is their speed? Answer in units of m/s

Answer 1

In meters per seconds, the speed of the elevators is 5.82m/s

Explanation:

Speed is distance divided by time.

In your problem, the distance is 897ft and the time is 47s. However, your distance is in ft and the answer of the problem is in m\s. So, we need to convert the distance from feet to m.

1 feet = 0.3048m.

So 897ft, in meters, is 897*(0.3048) = 273,4m.

Then, the speed of the elevators in this building will be 273,4m/47s = 5.82 m/s.