Question

H(x) = 2x^2 =4; Find h(-10)

Answer 1

For this case we have the following function:

`h (x) = 2x ^ 2 + 4`

We must find the value of the function when x = -10

So, replacing we have:

`h (-10) = 2 (-10) ^ 2 + 4\\h (-10) = 2 (100) +4\\h (-10) = 200 + 4\\h (-10) = 204`

Thus, the value of the function is 204 when x = -10

Answer:

`h (-10) = 204`