Question

The radius of a chromium atom is 125 pm. How many chromium atoms would have to be laid side by side to span a distance of 1.36 mm?

Answer 1

5,440,000 atoms

Step-by-step explanation:

The width (diameter) of a chromium atom is 250 pm (twice the radius). A picometer is equal to 10⁻⁹ millimeters, so the width of an atom is 250 x 10⁻⁹ mm

The number of atoms required to span of 1.36 mm is calculated as follows:

`(1.36)/(250 x 10^-9) = 5,440,000`