Question

If potential difference is reduced to half, the energy of capacitance will be

Answer 1

The formula of the capacitance is

`C=(q)/(V)`

If you half the potential difference, you'll have the new capacity

`C_1 = (q)/((V)/(2))=(2q)/(V) = 2\cdot(q)/(V)=2C`

So, if you half the potential difference, the capacitance doubles.