Question

7 and 1/3 - 2 and 1/2...how do i solve it

Answer 1

let's firstly convert the mixed fractions to improper fractions and then subtract.

`\bf \stackrel{mixed}{7(1)/(3)}\implies \cfrac{7\cdot 3+1}{3}\implies \stackrel{improper}{\cfrac{22}{3}}~\hfill \stackrel{mixed}{2(1)/(2)}\implies \cfrac{2\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{5}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{22}{3}-\cfrac{5}{2}\implies \stackrel{\textit{using an LCD of 6}}{\cfrac{(2)22~~-~~(3)5}{6}}\implies \cfrac{44-15}{6}\implies \cfrac{29}{6}\implies 4(5)/(6)`