Question

If the frog lands with a velocity equal to its average velocity and comes to a full stop 0.25s later, what is the frog’s average acceleration?

Answer 1

Average accelation = -4V

Step-by-step explanation:

`a=(V-V0)/(t)`

V=0 m/s (because the frog stopped)

V0 = V (average velocity)

t= 0,25 s

So;

`a=(V-V0)/(t)=(0-V)/(0.25)=-<strong>4V</strong>`