Question

Unpolarized light of intensity I=10 falls on two successive polarizer wheels with the angle between the polarizer wheels e-60°. What is the resultant intensity of the polarized light after leaving the 2nd polarizer? A) (0)/2 B) (10)/4 C) (0)/8 D) (o)/16

Answer 1

`I=(10)/(4)`

Step-by-step explanation:

A polarizer changes the orientation of the oscillations of a light wave.

I₀ = Intensity of unpolarized light = 10

θ = Angle given to the polarizer = 60°

Intensity of light

I = I₀cos²θ

⇒I = 10cos²60

`\\\Rightarrow I=10* (1)/(2)* (1)/(2)\\\Rightarrow I=(10)/(4)`

So, the after passing through the second polarizer is
`\mathbf{(10)/(4)}`