Question

When a 0.740-g sample of trinitrotoluene (TNT), C7H5N2O6, is burned in a bomb calorimeter, the temperature increases from 23.4 to 26.9 C the heat capacity of t he calorimeter is 534 j/C, and it contains 675 mL of water. How much heat was produced by the combusttion of the TNT sample?

Answer 1

Step-by-step explanation:

The given data is as follows.

mass of sample (X) = 0.740 g,
`T_(1)` =
`23.4 ^(o)C`

`T_(1)` =
`26.9 ^(o)C`

As, Density =
`(mass)/(volume)`

1.00 g/ml =
`(mass)/(675 ml)`

mass = 675 g

Hence, weight of water = 675 g and heat capacity is given as 534
`J/ ^(o)C`

Heat produced by combustion of TNT = Heat gained by the water

`W * C * \Delta T` =
`X * Heat`

Heat =
`(W * C * \Delta T)/(X)`

=
`(675 g * 534 J/C * (26.6 - 23.4)^(o)C)/(0.740 g)`

= 1704831 J

As 1 kJ = 1000 J. So, 1704831 J = 1704.831 kJ

Thus, we can conclude that heat produced by the combustion of the TNT sample is 1704.831 kJ.