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An 80 kg man descends to the ground from an aeroplane using a parachute. If the drag coefficient of the parachute is 0.5 and the density of air is 1.35 kg/m3, calculate the required diameter of the parachute so that the man descends with a velocity of 25 m/s.

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Answer:

Explanation:2.17 m

Given

Mass of man=80 kg

drag coefficient
(c_D)=0.5

Density of air
=1.35 kg/m^3

Required descend velocity(v)=25 m/s

Let d be the diameter of Parachute

In this case Drag force will oppose weight of man so that net force is zero and there is a constant velocity of descend


W=F_L


F_L=(c_DA\rho v^2)/(2)

W=mg


80* 9.81=(0.5* (\pi d^2)/(4)* 1.35* 25^2)/(2)


784.8=165.691* d^2

d=2.17 m

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