Question

Calculate the mutual force of repulsion between two charged spheres 2 cm apart of the repulsive force for a 1 cm separation is 16 N.

Answer 1

4 N is the mutual force of repulsion between two charged spheres 2 cm apart if the repulsive force for a 1 cm separation is 16 N.

Answer 2

Force of repulsion is 4 N.

Step-by-step explanation:

It is given that,

If separation between the charged sphere, r = 1 cm = 0.01 m

Force of repulsion, F = 16 N

We need to find the force of repulsion (F') when the separation between the spheres is r' = 2 cm = 0.02 m

The force of attraction or repulsion is given by :

`F=k(q_1q_2)/(r^2)`

i.e.
`F\propto (1)/(r^2)`

So,
`(F)/(F')=(r'^2)/(r^2)`

`(16)/(F')=(0.02^2)/(0.01^2)`

F' = 4 N

So, the force of repulsion between the spheres is 4 N when the separation is 2 cm. Hence, this is the required solution.