Question

Hooke’s Law of Elasticity states that the force applied, y, varies directly with the distance a spring stretches, x (assuming the spring is not stretched past its elastic limit). If a force of 160 newtons stretches a spring 800 cm, how far will a force of 368 newtons stretch the same spring? Justify your answer.

Group of answer choices

F. It will stretch the same spring 73.6 cm because the equation is y equals 5x.

G. It will stretch the same spring 73.6 cm because the equation is y equals one fifth x..

H. It will stretch the same spring 1,840 cm because the equation is y equals 5x.

J. It will stretch the same spring 1,840 cm because the equation is y equals one fifth x..

Answer 1

H: It will stretch the same spring 1,840 cm because the equation is y equals 5x.

Explanation:

800=y

160and368=x

You find the answer by dividing,

⁸⁰⁰⁄₁₆₀= ʸ⁄₃₆₈

800 divided by 160 equals 5 which means the equation is y equals 5x

and 368x5=1,840

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