Question

Find the slope and y-intercept of the line that is perpendicular to

y= —1/3x + 5 and passes through the point (—3, —7)

Answer 1

The line is
`y = 3x + 2`

Explanation:

For one line to be perpendicular to the other, the lines must have negative reciprocal slopes. The slope in the given function is -1/3, so the slope of the other line is 3

We're given an ordered pair, so we can use the equation
`y = mx + b` to solve for the y intercept

`-7 = 3(-3) + b\\-7 = -9 + b\\b = 2`

The line is
`y = 3x + 2`