Answer:
4p
Step-by-step explanation:
The possible orbitals in an electronic configuration must include:
A principle quantum number (n) , azimuthal quantum number (l) which is (0-n-1) , magnetic quantum number (m) which is (-l to +l) and spin quantum number.
Taking about 1p
n = 1
Possible value of l = 0 which is s orbital. Hence, it is not possible.
Taking about 3f
n = 3
Possible value of l = 0 , 1 and 2 which is s , p and d orbitals. Hence, it is not possible.
Taking about 2d
n = 2
Possible value of l = 0 and 1 which is s and p orbitals. Hence, it is not possible.
The only possible is 4 p in which all quantum numbers are justified.