A proton is trapped in a one-dimensional well that is 200 pm wide. What is the ground state energy of the proton, if the potential is zero at the bottom of the well?

Question

asked Mar 3, 2020 38.4k views

1 Answer

Ahsan Farooq · Answer 1 · 2020-03-09T10:18:31+0000

Answer:

E=1.50\times 10^{-18}J

Step-by-step explanation:

Energy of the one dimensional infinite well,

E=(n^(2)h^(2) )/(8mL^(2) )

Given that,
$L=200 pm\\L=200* 10^(-12)m$

For the ground state n=1,

Therefore energy is,

$E=((6.626* 10^(-34))^(2))/(8(9.1* 10^(-31))(200* 10^(-12)) ^(2) )\\E=1.50* 10^(-18)J$