What is the grating separation (d) that corresponds to a source of wavelength 530.5 nm that produces a line at 44.2°? Calculate this value in nm using m=1.

Question

asked Jan 25, 2020 104k views

1 Answer

Arcol · Answer 1 · 2020-01-29T19:28:35+0000

Answer:

761 nm

Step-by-step explanation:

We have given the wavelength of source
$\lambda =530.5nm=530.5* 10^(-9)m$

Angle
$\Theta =44.2^(\circ)$

In question it is said that use m= 1

We have to find grating separation

According to law of diffraction

$dsin\Theta =m\lambda$

dsin44.2 =1* 530.5* 10^(-9)

d=761nm