A reaction of 2.5kg of fissionable material takes place. Assuming a 0.10% mass defect, how much energy is released?

Question

asked Sep 2, 2020 110k views

1 Answer

Sakiko · Answer 1 · 2020-09-08T04:18:02+0000

Answer:

Energy released =
$2.25* 10^(14)\;J$

Step-by-step explanation:

Amount of fissionable material = 2.5 kg

Mass defect = 0.10 % of fissionable material

Mass defect
$=2.5* (0.1)/(100) = 0.0025\; kg$

E = mc^(2)

Where,

m = Mass defect in Kg

C = Speed of light m/s2

$C = 3* 10^(8)\;m/s^2$

Now substitute the values in the above equation

$E = 0.0025* (3* 10^(8))^2 = 2.25* 10^(14)\;J$