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If 5.58 g of iron reacts with sulfur to produce 8.79 g of iron sulfide, what is the mass of reacting sulfur? A) 3215 B) 14:37 C) 8.798 D) 5.58 g E) impossible to predict from the given information

1 Answer

2 votes

Answer: A) 3.21 g

Step-by-step explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side.


Fe+S\rightarrow FeS

We are given:

Mass of iron = 5.58 g

Mass of iron sulphide = 8.79 g

Mass of sulphur = x g

Total mass on reactant side = 5.58 + x

Total mass on product side = 8.79 g

Applying law of conservation of mass, we get:


5.58+x=8.79\\\\x=3.21g

Hence, the mass of reacting sulfur is 3.21 g.

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User ZombieBatman
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