What is the volume of soup that will fit in a cylindrical-shaped can with a height that is 2 inches longer than the radius?

Question

asked Jun 13, 2020 206k views

2 Answers

Gotit · Answer 1 · 2020-06-14T17:37:59+0000

Answer:

V = πr³ + 2πr²

Explanation:

Volume of a cylinder:

V = πr²h

with radius r and height h = 2 + r:

V = πr²(2 + r) = πr³ + 2πr²

Yuiko · Answer 2 · 2020-06-18T17:16:22+0000

Answer:
$V=\pi r^3+2\pi r^2$

Explanation:

Let r be the height of the cylinder then , the height of the cylinder will be (r+2).

The formula to find the volume of cylinder is given by :-

$V=\pi r^2h$

Then, the volume of the cylinder will be :-

$V=\pi r^2((r+2))\\\\\Rightarrow\ V=\pi r^2(r)+\pi r^2(2)\\\\\Rightarrow\ V=\pi r^3+2\pi r^2$

Hence, the volume of soup that will fit in a cylindrical-shaped can with a height that is 2 inches longer than the radius =
$V=\pi r^3+2\pi r^2$