Question

For the following equilibrium: 3A + B = 20 If equilibrium concentrations are [A] = 1.1 M and [B] = 1.4 M, and Kc = 11.3, what is the equilibrium concentration of C? • Your answer should have two significant figures. Provide your answer below:

Answer 1

Answer : The equilibrium concentration of C is 4.6 M

Solution : Given,

Concentration of
`A` at equilibrium = 1.1 M

Concentration of
`B` at equilibrium = 1.4 M

`K_c=11.3`

First we have to calculate the value of equilibrium constant.

The given equilibrium reaction is,

`3A+B\rightleftharpoons 2C`

The expression of
`K_c` will be,

`K_c=([C]^2)/([A]^3[B])`

`11.3=([C]^2)/((1.1)^3* (1.4))`

`[C]=4.6M`

Therefore, the equilibrium concentration of C is 4.6 M