Question

A 40.0 mL sample of 0.18 M HCI is titrated with 0.36 M CoHsNH2. Dctermine the pH at these points: At the beginning (before base is added) a. show work Ph+Lg hox 0-ip 0-30 34 X10-10 K =3. 9x 10 O

Answer 1

at the beginning:

pH = 0.745

Step-by-step explanation:

HCl is a strong acid, so:

• HCl + H2O → H3O+ + Cl-

0.18 M 0.18 0.18.....equilibrium

before base is added:

∴ [ H3O+ ] ≅ C HCl = 0.18 M

⇒ pH = - Log [ H3O+ ] = - Log ( 0.18 )

⇒ pH = 0.745