Question

A circular loop of wire of radius 0.50 m is in a uniform magnetic field of 0.30 T. The current in the loop is 2.0 A. What is the magnetic torque when the plane of the loop is perpendicular to the magnetic field? A) 0.59 m-N B) zero C) 0.41 m-N D) 0.52 m N E 0.47 m-N

Answer 1

Magnetic torque on the coil is 0.47 N-m.

Step-by-step explanation:

It is given that,

Radius of the circular loop, r = 0.5 m

Magnetic field, B = 0.3 T

Current in the loop, I = 2 A

We need to find the magnetic torque when the plane of the loop is perpendicular to the magnetic field. The magnetic torque is given by :

`\tau=BIA\ sin\theta`

`\theta=90^(\circ)`

`\tau=BI\pi r^2`

`\tau=0.3* 2* \pi * (0.5)^2`

`\tau=0.47\ N-m`

So, the magnetic torque on the coil is 0.47 N-m. Hence, this is the required solution.