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14. Write an expression for the output voltage of an ac source that has an amplitude of 12 V and a frequency of 200 Hz

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User Sji
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1 Answer

4 votes

Answer:


v = 12sin400\pi t

Given:

Voltage,
v_(m) = 12 V

frequency, f = 200 Hz

Solution:

The expression for output voltage of an AC source is given by:


v = v_(m)sin\omega t

where


\omega = 2\pi f

Therefore,


v = v_(m)sin2\pi f t

Now, using the given values in the output voltage expression for an ac source:


v = 12sin2\pi * 200

Thus the expression so formed is:


v = 12sin400\pi t

answered
User Betseyb
by
8.3k points

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