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The sum of three consecutive odd intergers is 17 less that four the smallest interger?​

asked
User Suresiva
by
7.8k points

1 Answer

4 votes

Answer:

The integers are 23, 25, 27

Explanation:

the sum of three consecutive odd integers


S = x + (x+2) + (x + 4)\\

17 less than four the smallest integer


S = 4x-17

Now set them equal and solve


4x-17 = 3x + 6\\x = 23

answered
User Offir
by
7.8k points

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