Estimate the uncertainty in energy during a time interval of 10-23 s. Express your answer in MeV

Question

asked Sep 18, 2020 46.8k views

1 Answer

Rump Roast · Answer 1 · 2020-09-22T18:09:17+0000

Answer:

The uncertainty in energy during a time interval is
$2.52375*10^(-23)\ Mev$

Step-by-step explanation:

Given that,

Time
$\Delta t= 10-23= 13 s$

We need to calculate the uncertainty in energy

Using uncertainty principle

$\Delta E \Delta t \geq (\hbar)/(2)$

$\Delta E \geq(\hbar)/(2\Delta t)$

Put the value into the relation

$\Delta E=(1.05*10^(-34))/(2*13)$

$\Delta E\geq 4.038*10^(-36)\ J$

$\Delta E\geq (4.038*10^(-36))/(1.6*10^(-19))$

$\Delta E\geq 2.52375*10^(-17)\ ev$

$\Delta E\geq(2.52375*10^(-17))/(10^(6))\ MeV$

$\Delta E\geq 2.52375*10^(-23)\ Mev$

Hence, The uncertainty in energy during a time interval is
$2.52375*10^(-23)\ Mev$