Question

a bag contains 6 red marbles 4 blue marbles 7 green marbles and 3 yellow marbles a marble is drawn from the bag and is not replaced then a second ball is drawn what is the probability that both marbles drawn were red

Answer 1

Answer:
`\bold{(3)/(38)=7.9\%}`

Explanation:

There are 20 total marbles and 6 of them are red.

The first draw has a probability of 6 red out 20 total marbles.

The second draw has a probability of 5 remaining red out of 19 remaining marbles

1st draw and 2nd draw

`(6)/(20)` ×
`(5)/(19)`
`=(30)/(380)\qquad =(3)/(38)\qquad =7.9\%`